WebJul 5, 2013 · My stored procedure receives a parameter which is a comma-separated string: DECLARE @Account AS VARCHAR (200) SET @Account = 'SA,A' I need to make from it this statement: WHERE … WebConvert comma separated String to List. List items = Arrays.asList(str.split("\\s*,\\s*")); The above code splits the string on a delimiter defined as: zero or more whitespace, a literal comma, zero or more whitespace which will place the words into the list and collapse any whitespace between the words and commas.
sql server - Join with comma separated values in SQL without …
WebFeb 7, 2024 · In SQL Server 2016 your query should be as simple as: declare @tab table ( [user_name] varchar (10),Unit varchar (100)) insert into @tab VALUES ('ABC','1,2') SELECT t. [user_name] , Value as Unit FROM @tab t CROSS APPLY STRING_SPLIT (t.Unit , ',') Share Improve this answer Follow answered Feb 7, 2024 at 9:14 M.Ali 67.2k 13 99 124 … WebFeb 28, 2024 · A. Generate list of names separated in new lines The following example produces a list of names in a single result cell, separated with carriage returns. SQL USE AdventureWorks2024 GO SELECT STRING_AGG (CONVERT(NVARCHAR(max),FirstName), CHAR(13)) AS csv FROM Person.Person; … sanders committee
Using a comma-separated parameter in an IN clause
WebDec 22, 2014 · If you are using SQL 2016 and above string_split you can use. -- @param is where you keep your comma separated values example: declare @param = 'param1,param2,param3' select * from table1 where col1 in (select TRIM (value) from string_split (@param,',') More information about string_split check offical documemt WebMay 28, 2024 · 2 Answers. Sorted by: 11. Below is for BigQuery Standard SQL. #standardSQL SELECT * EXCEPT (c) REPLACE (c AS country) FROM `project.dataset.table`, UNNEST (SPLIT (country)) c. If to apply to sample data from your question as in below example. #standardSQL WITH `project.dataset.table` AS ( SELECT … WebJan 2, 2012 · 5 Answers. DECLARE @List VARCHAR (8000) SELECT @List = COALESCE (@List + ',', '') + CAST (OfferID AS VARCHAR) FROM Emp WHERE EmpID = 23 SELECT @List. This approach to aggregate concatenation is not guaranteed to work. If you are on at least SQL Server 2005 XML PATH or CLR aggregates are preferred. The … sanders county 411 uncensored