site stats

Show that 12 n cannot end with zero or 5

WebGrievance procedure mor mortgage broker mentorship program/title ... WebThe prime factors of 12 are 2 and 3. 12 = 2 2 × 3 ⇒ 12 n = 2 2 n × 3 n Since, 5 is not the factor of 12 n Therefore, for any value of n, 12 n will not be divisible by 5. Hence, 12 n cannot end with the digit 0 or 5 for any value of n. Disclaimer: The question is: 12 n cannot end with the digit 0 or 5 for _______ value of n. Suggest Corrections 1

show that 12 to the power n cannot end with the digit 0 or 5 for …

WebIf 12 n ends with the digit zero or five it should be divisible by 5. It is possible if prime factorisation of 12 n has the prime number 5. 12 = 2 × 2 × 3 = 22 × 3. 12 n = (22 × 3) n = 22 … WebJan 18, 2024 · See answer. 12 to the power n cannot end with the digit 0 or 5 because for a number to end with the digit 0 or 5,it should have 2 and 5 both in its prime factorization. … hint ceo removed https://dynamikglazingsystems.com

show that 12 to the power n cannot end with the digit 0 or 5 for any

WebApr 21, 2024 · For a number to be end with digit zero its prime factors must have atleast one 2 and A are 5 both and for a number to be end with 5 its prime factors must have at least … Webnews presenter, entertainment 2.9K views, 17 likes, 16 loves, 62 comments, 6 shares, Facebook Watch Videos from GBN Grenada Broadcasting Network: GBN News 12th April 2024 Anchor: Stasia Blake GBN... WebFor a number to end with 0, the number must have 2 & 5 as factors. 10=2×5 100=2 2×5 2 For a number to end with 5, the number must have 5 as a factor. 30=5×6 3 n×(2 2) m=3 n×2 2m This number dosent have 5 or 5 and 2 as its factors. Therefore the number cant end with 0 o 5. Was this answer helpful? 0 0 Similar questions hint ceo

show that 12 to the power n cannot end with the digit 0 or 5 for …

Category:Show that (12)n cannot end with digit

Tags:Show that 12 n cannot end with zero or 5

Show that 12 n cannot end with zero or 5

Show that (12)n cannot end with digit

WebThe prime factors of 12 are 2 and 3. 12 = 2 2 × 3 ⇒ 12 n = 2 2 n × 3 n Since, 5 is not the factor of 12 n Therefore, for any value of n, 12 n will not be divisible by 5. Hence, 12 n … WebShow that 9^n cannot end with the digit 2 for any n in N. Show that 9^n cannot end with the digit 2 for any n in N. ... Show that `12^(n)` cannot end with digit 0 or 5 for any natural number n. 44675. 2.7 K+. 3.2 K+. 3:26. Show that `12^n` cannot end with the digits `0` or `5` for any natural number `n` 648305496.

Show that 12 n cannot end with zero or 5

Did you know?

WebOct 10, 2024 · If 12 n ends with the digit zero it must be divisible by 5. This is possible only if the prime factorisation of 12 n contains the prime number 5. The prime factorisation of 12 … WebShow that 12 n cannot end with the digit 0 or 5 for any natural number n. Answers (1) We know that, if any number ends up with digit 0 or 5 then it must be divisible by 5. Here 12n …

WebApr 25, 2024 · The largest number which divides 70 and 125, leaving remainders 5 and 8, respectively, is (A) 13 (B) 65 (C) 875 (D) 1750 Solution: (A) Since 5 and 8 are the remainders of 70 and 125, respectively. Thus, after subtracting these remainders from the numbers, we have the numbers (70 – 5) = 65, (125 – 8) = 117 which are divisible by the required number. WebShow that 12n cannot end with the digit 0 or 5 for any natural number n. If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be …

WebFor smallish numbers, you could try getting a multiple of 6 = 1 + 5 close to your number, find the number of zeroes for 25 / 6 times that and try to revise your estimate. For example for 156 = 6 ∗ 26. So try 26 ∗ 5 ∗ 5 = 650. 650! has 26 ∗ 5 + 26 + 5 + 1 = 162 zeroes. Since you overshot by 6, try a smaller multiple of 6.

WebJul 17, 2014 · 25 n = (5 X 5) n If we raise 5 to any power ,unit digit will only be 5 . For any natural number to end with 0 , it must be a factor of 10 so it must have factors both 2 and 5 .But 25 does not have 2 as a factor. Thus 25 n cannot end with 0 for any natural number n Hope this would have cleared your doubt .

WebApr 11, 2024 · 4.3K views, 492 likes, 148 loves, 70 comments, 48 shares, Facebook Watch Videos from NET25: Mata ng Agila International April 11, 2024 homepop storage benchWebNov 27, 2024 · Solution: If the number 12n, for any natural number n, ends with the digit 0 or 5, then it is divisible by 5. That is, the prime factorization of 12n contains the prime 5. This … homepop storage entryway benchWebTo Show :- 12 n cannot end with 0 Proof :-12 n = 4 n x 3 m = 2 n x 3 m But the formula of factorisation tells that the numbers can end with 0 or 5 when they are in form of 2 n + 5 m … hint cards